document.write( "Question 978260: A mother is 25 years older than her daughter. In 10 years, she will be twice as old as her daughter. Determine their present age \n" ); document.write( "
Algebra.Com's Answer #599741 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "A mother is 25 years older than her daughter \n" ); document.write( "M = 25 + D \n" ); document.write( "In 10 years, she will be twice as old as her daughter. \n" ); document.write( "M + 10 = 2(D + 10) \n" ); document.write( "Replace M with 25 + D \n" ); document.write( "25 + D + 10 = 2(D + 10) \n" ); document.write( "25 + D + 10 = 2D + 20 \n" ); document.write( "Collect like terms \n" ); document.write( "D - 2D = 20 - 25 - 10 \n" ); document.write( "-D = -15 \n" ); document.write( "Multiply both sides by -1 \n" ); document.write( "D = 15 \n" ); document.write( "Therefore present ages: \n" ); document.write( "Daughter = 15 yrs old \n" ); document.write( "Mother = 40 years old. \n" ); document.write( "Hope this helps:-) \n" ); document.write( " |