document.write( "Question 978260: A mother is 25 years older than her daughter. In 10 years, she will be twice as old as her daughter. Determine their present age \n" ); document.write( "
Algebra.Com's Answer #599741 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( "A mother is 25 years older than her daughter
\n" ); document.write( "M = 25 + D
\n" ); document.write( "In 10 years, she will be twice as old as her daughter.
\n" ); document.write( "M + 10 = 2(D + 10)
\n" ); document.write( "Replace M with 25 + D
\n" ); document.write( "25 + D + 10 = 2(D + 10)
\n" ); document.write( "25 + D + 10 = 2D + 20
\n" ); document.write( "Collect like terms
\n" ); document.write( "D - 2D = 20 - 25 - 10
\n" ); document.write( "-D = -15
\n" ); document.write( "Multiply both sides by -1
\n" ); document.write( "D = 15
\n" ); document.write( "Therefore present ages:
\n" ); document.write( "Daughter = 15 yrs old
\n" ); document.write( "Mother = 40 years old.
\n" ); document.write( "Hope this helps:-)
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