document.write( "Question 978305: Can you help me solve this problem?
\n" ); document.write( "The perimeter is 38 Meters and its area is 84 square meters, find its dimension.\r
\n" ); document.write( "\n" ); document.write( "Hope you can help me :)
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Algebra.Com's Answer #599737 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Hi there,
\n" ); document.write( "Perimeter = 2 x Length + 2 x Width
\n" ); document.write( "Area = Length x Width
\n" ); document.write( "...........
\n" ); document.write( "Area = Length x Width
\n" ); document.write( "84 = Length x Width
\n" ); document.write( "Width = 84/Length
\n" ); document.write( "Substitute W = 84/L into perimeter
\n" ); document.write( "Perimeter = 2 x Length + 2 x Width
\n" ); document.write( "38 = 2L + 2(84/L)
\n" ); document.write( "38 = 2L + 168/L
\n" ); document.write( "Multiply thro'out by L
\n" ); document.write( "38L = 2L^2 + 168
\n" ); document.write( "Sort into equation
\n" ); document.write( "(ax^2 + bx + c = 0)
\n" ); document.write( "2L^2 - 38L + 168 = 0
\n" ); document.write( "Divide through by 2
\n" ); document.write( "L^2 - 19L + 84 = 0
\n" ); document.write( "Factorise
\n" ); document.write( "(L - 7)(L - 12) = 0
\n" ); document.write( "Therefore L = 7m W = 12m
\n" ); document.write( "or L = 12m W = 7m
\n" ); document.write( "Hope this helps:-)
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