document.write( "Question 978141: the line y=2x+7 is parallel to the line y=2x-3.The line y= -0.5x+7 is perpendicular to the line y=2x-3. Find the perpendicular distance between the pair of parallel lines. \n" ); document.write( "
Algebra.Com's Answer #599708 by KMST(5328)\"\" \"About 
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Line \"blue%28y=2x-3%29\" is parallel to line \"red%28y=2x%2B7%29\" ,
\n" ); document.write( "which is perpendicular to \"green%28y=-0.5x%2B7%29\" ,
\n" ); document.write( "so \"blue%28y=2x-3%29\" and \"green%28y=-0.5x%2B7%29\" are perpendicular to each other.
\n" ); document.write( "So the distance between \"blue%28y=2x-3%29\" and \"red%28y=2x%2B7%29\"
\n" ); document.write( "is the distance, along \"green%28y=-0.5x%2B7%29\" ,
\n" ); document.write( "between the points where \"green%28y=-0.5x%2B7%29\" intersects the other two lines.
\n" ); document.write( "Lines \"green%28y=-0.5x%2B7%29\" and \"red%28y=2x%2B7%29\" obviously intersect at point \"Q%280%2C7%29\" , the y-intercept for both lines.
\n" ); document.write( "We can find the point \"P\" where \"green%28y=-0.5x%2B7%29\" and \"blue%28y=2x-3%29\" intersect
\n" ); document.write( "by solving \"system%28green%28y=-0.5x%2B7%29%2Cblue%28y=2x-3%29%29\"
\n" ); document.write( "I wanted to graph anyway, and in the graph it looked like it was \"P%284%2C5%29\" .
\n" ); document.write( "Substituting \"x=4\" to see that \"y=5\" for both lines confirmed that solution:
\n" ); document.write( "\"green%28y=-0.5%2A4%2B7=-2%2B7=5%29\" and \"blue%28y=2%2A4-3=8-3=5%29%29\"\r
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\n" ); document.write( "The distance from \"Q%7B0%2C7%29\" and \"P%284%2C5%29\"
\n" ); document.write( "is the distance between \"red%28y=2x%2B7%29\" and \"blue%28y=2x-3%29\" .
\n" ); document.write( "The distance between two points can be calculated according to a formula:
\n" ); document.write( "\"PQ=sqrt%28%28x%5BP%5D-x%5BQ%5D%29%5E2%2B%28y%5BP%5D-y%5BQ%5D%29%5E2%29\" ,
\n" ); document.write( "but there is no need (usually) to memorize formulas,
\n" ); document.write( "if you understand their meaning.
\n" ); document.write( "That distance is the hypotenuse of a right triangle,
\n" ); document.write( "like the one in my drawing,
\n" ); document.write( "whose legs, parallel to the x-axis and y-axis,
\n" ); document.write( "are the horizontal distance and the vertical distance between the points.
\n" ); document.write( "In this case,
\n" ); document.write( "\"distance=sqrt%284%5E2%2B2%5E2%29=sqrt%2816%2B4%29=sqrt%2820%29=2sqrt%285%29=about4.47\"(rounded).
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