document.write( "Question 978200: The one to one function f is defined on the domain x>0 by f(x) = (2x-1)/(x+2).
\n" ); document.write( "A) State the range, A, of f.
\n" ); document.write( "B) Obtain an expression for f^(-1) (x) for x∈A.\r
\n" ); document.write( "\n" ); document.write( "I am assuming that the letter A is only a variable used to represent the range of f(x). If that is the case, how can an expression be made for the inverse function?
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Algebra.Com's Answer #599665 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
\"%282%2Af%5E%28-1%29-1%29%2F%28f%5E%28-1%29%2B2%29=x\"\r
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\n" ); document.write( "\n" ); document.write( "That expression is essentially switching the places or roles of x and y. You want a function that will give you x.\r
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\n" ); document.write( "\n" ); document.write( "Try not using the \"...to the negative one power\" type notation. You want a function g(x) so that f(x) and g(x) will undo each other. That means that \"g%28f%28x%29%29=f%28g%28x%29%29=x\".\r
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\n" ); document.write( "\n" ); document.write( "You have your specific definition for f(x). You want to use some other function g(x) AS INPUT to f(x) and the OUTPUT must be x.\r
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\n" ); document.write( "\n" ); document.write( "\"system%28g%28x%29=YouNotYetKnow%2Cf%28x%29=%282x-1%29%2F%28x%2B2%29%2Cf%28g%28x%29%29=x%29\".\r
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\n" ); document.write( "\n" ); document.write( "Form that last-specified composition:
\n" ); document.write( "\"%282%2Ag%28x%29-1%29%2F%28g%28x%29%2B2%29=x\"\r
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\n" ); document.write( "\n" ); document.write( "Solve that equation for g(x).
\n" ); document.write( "The inverse of f(x) will be g(x).
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