document.write( "Question 978195: Mr. Cruz bought a rectangular lot if he needed 78 metres of chicken wire to fence the whole lot which is 368 square meters, what are the dimensions of the lot? \n" ); document.write( "
Algebra.Com's Answer #599658 by Cromlix(4381) You can put this solution on YOUR website! Hi there, \n" ); document.write( "Perimeter = 2 x Length + 2 x Width \n" ); document.write( "78 = 2L x 2W \n" ); document.write( "........... \n" ); document.write( "Area = Length x Width \n" ); document.write( "368 = LW \n" ); document.write( "So, W = 368/L \n" ); document.write( "Substitute \n" ); document.write( "W = 369/L into \n" ); document.write( "78 = 2L + 2W \n" ); document.write( "78 = 2L + 2(368/L) \n" ); document.write( "Multiply out \n" ); document.write( "78 = 2L + 736/L \n" ); document.write( "Multiply both sides by L \n" ); document.write( "78L = 2L^2 + 736 \n" ); document.write( "Sort out \n" ); document.write( "2L^2 - 78L + 736 = 0 \n" ); document.write( "Divide thr'out by 2 \n" ); document.write( "L^2 - 39L + 368 = 0 \n" ); document.write( "Factorise \n" ); document.write( "(L - 16)(L - 23)= 0 \n" ); document.write( "Length = 16m and Width = 23m \n" ); document.write( "or Length = 23m and Width = 16m \n" ); document.write( "Hope this helps:-) \n" ); document.write( " |