document.write( "Question 978195: Mr. Cruz bought a rectangular lot if he needed 78 metres of chicken wire to fence the whole lot which is 368 square meters, what are the dimensions of the lot? \n" ); document.write( "
Algebra.Com's Answer #599658 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Hi there,
\n" ); document.write( "Perimeter = 2 x Length + 2 x Width
\n" ); document.write( "78 = 2L x 2W
\n" ); document.write( "...........
\n" ); document.write( "Area = Length x Width
\n" ); document.write( "368 = LW
\n" ); document.write( "So, W = 368/L
\n" ); document.write( "Substitute
\n" ); document.write( "W = 369/L into
\n" ); document.write( "78 = 2L + 2W
\n" ); document.write( "78 = 2L + 2(368/L)
\n" ); document.write( "Multiply out
\n" ); document.write( "78 = 2L + 736/L
\n" ); document.write( "Multiply both sides by L
\n" ); document.write( "78L = 2L^2 + 736
\n" ); document.write( "Sort out
\n" ); document.write( "2L^2 - 78L + 736 = 0
\n" ); document.write( "Divide thr'out by 2
\n" ); document.write( "L^2 - 39L + 368 = 0
\n" ); document.write( "Factorise
\n" ); document.write( "(L - 16)(L - 23)= 0
\n" ); document.write( "Length = 16m and Width = 23m
\n" ); document.write( "or Length = 23m and Width = 16m
\n" ); document.write( "Hope this helps:-)
\n" ); document.write( "
\n" );