document.write( "Question 978177: we we're asked to form the inequality of this problem and solve.... can you pls help me??
\n" ); document.write( "This is the problem:\r
\n" ); document.write( "\n" ); document.write( "The ages in years of 3 brothers are consecutive multiples of 4. Three years ago, the sum of their ages was less than 39. Find their present ages.\r
\n" ); document.write( "\n" ); document.write( "thank you, in advance!!
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Algebra.Com's Answer #599639 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
consecutive ages are 4x, 4(x+1), 4(x+2)
\n" ); document.write( "4x-3 + 4x+4-3 + 4x+8-3 < 39
\n" ); document.write( "4x-3 + 4x+1 + 4x+5 < 39
\n" ); document.write( "12x + 3 < 39
\n" ); document.write( "12x < 36
\n" ); document.write( "x < 3
\n" ); document.write( "There are two solutions to this problem
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\n" ); document.write( "1) x = 2
\n" ); document.write( "ages are 8, 12, 16
\n" ); document.write( "5 + 9 + 13 < 39
\n" ); document.write( "27 < 39
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\n" ); document.write( "2) x = 1
\n" ); document.write( "ages are 4, 8, 12
\n" ); document.write( "1 + 5 + 9 < 39
\n" ); document.write( "15 < 39
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