document.write( "Question 82992This question is from textbook introductory algebra
\n" ); document.write( ": a coumputer online service charges one hourly price for regular use but a higher hourly rate for designated \" permium\" areas. one customer was charged $28 after spending 2 h in permium areas and 9 regular hours another spent 3 h in the permium areas and 6 regular hours and was charged $27. what does the online service charge per hour for regulae and premium service? \n" ); document.write( "
Algebra.Com's Answer #59961 by ankor@dixie-net.com(22740)\"\" \"About 
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a computer on-line service charges one hourly price for regular use but a higher hourly rate for designated \" premium\" areas. one customer was charged $28 after spending 2 h in premium areas and 9 regular hours another spent 3 h in the premium areas and 6 regular hours and was charged $27. what does the on-line service charge per hour for regular and premium service?
\n" ); document.write( ":
\n" ); document.write( "x = charge for premium area
\n" ); document.write( "y = charge for regular area
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each customer:
\n" ); document.write( "2x + 9y = 28
\n" ); document.write( "3x + 6y = 27
\n" ); document.write( ":
\n" ); document.write( "Multiply 1st equation by 3, and the 2nd equation by 2:
\n" ); document.write( "6x + 27y = 84
\n" ); document.write( "6x + 12y = 54
\n" ); document.write( "---------------subtracting eliminates x
\n" ); document.write( "0x + 15y = 30
\n" ); document.write( "y = 30/15
\n" ); document.write( "y = $2/hr is the cost of regular service
\n" ); document.write( ":
\n" ); document.write( "Find x using 2x + 9y = 28; substitute 2 for y:
\n" ); document.write( "2x + 9(2) = 28
\n" ); document.write( "2x + 18 = 28
\n" ); document.write( "2x = 28 - 18
\n" ); document.write( "2x = 10
\n" ); document.write( "x = 10/2
\n" ); document.write( "x = $5/hr is cost of premium service
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution in the 2nd equation:
\n" ); document.write( "3(5) + 6(2) = 27
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