document.write( "Question 978068: The upper limit of the 90% confidence interval for the population proportion p, given that n = 100; and = 0.20 \n" ); document.write( "
Algebra.Com's Answer #599605 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! CI=1.645 +/- SE\r \n" ); document.write( "\n" ); document.write( "SE= sqrt {(0.2)(0.8)/100} \n" ); document.write( "=0.4/10, because sqrt (0.16)=0.4 \n" ); document.write( "=0.04\r \n" ); document.write( "\n" ); document.write( "CI=1.645*0.04=0.0658 \n" ); document.write( "upper limit is 0.2658\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |