document.write( "Question 978068: The upper limit of the 90% confidence interval for the population proportion p, given that n = 100; and = 0.20 \n" ); document.write( "
Algebra.Com's Answer #599605 by Boreal(15235)\"\" \"About 
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CI=1.645 +/- SE\r
\n" ); document.write( "\n" ); document.write( "SE= sqrt {(0.2)(0.8)/100}
\n" ); document.write( "=0.4/10, because sqrt (0.16)=0.4
\n" ); document.write( "=0.04\r
\n" ); document.write( "\n" ); document.write( "CI=1.645*0.04=0.0658
\n" ); document.write( "upper limit is 0.2658\r
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