document.write( "Question 11682: The perimeter of a rectangle is 32 inches and the area is 60 square inches. Find the length and the width of the rectangle.\r
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document.write( "I drew a rectangle and labled the sides x and y.
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document.write( "I wrote the following two exuations:
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document.write( "2x+2y=32 and xy=60.
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document.write( "I am now stuck. Can you help, please? \n" );
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Algebra.Com's Answer #5996 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! perfect so far....\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x+2y=32 and xy=60 \n" ); document.write( "--> x+y=16 and xy=60 \n" ); document.write( "--> y = 16-x \n" ); document.write( "--> x(16-x)=60 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so we have a quadratic, which needs to be solved. Hopefully by factorisation. If not..the quadratic formula.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1x60 \n" ); document.write( "2x30 \n" ); document.write( "3x20 \n" ); document.write( "4x15 \n" ); document.write( "5x12 \n" ); document.write( "6x10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "looking at these, 6 and 10 can add to make 16, so\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-10)(x-6) = 0 \n" ); document.write( "so x-10=0 OR x-6=0 \n" ); document.write( "so x=10 OR x=6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, basically we have x=10, so y=6 \n" ); document.write( "or we have the opposite, x=6 and y=10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon. \n" ); document.write( " \n" ); document.write( " |