document.write( "Question 83449: solve and check your solutions\r
\n" ); document.write( "\n" ); document.write( "square root of 2y+7+4=y
\n" ); document.write( "

Algebra.Com's Answer #59952 by uma(370)\"\" \"About 
You can put this solution on YOUR website!
2y+7+4=y\r
\n" ); document.write( "\n" ); document.write( "==> 2y + 11 = y\r
\n" ); document.write( "\n" ); document.write( "adding -y to both the sides,\r
\n" ); document.write( "\n" ); document.write( "2y + 11 - y = 0\r
\n" ); document.write( "\n" ); document.write( "adding -11 to both the sides.\r
\n" ); document.write( "\n" ); document.write( "y + 11 -11 = -11\r
\n" ); document.write( "\n" ); document.write( "=> y = -11\r
\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "2y+7+4=y
\n" ); document.write( "Replacing y by -11,
\n" ); document.write( "2(-11) + 11 = -11\r
\n" ); document.write( "\n" ); document.write( "==> -22 + 11 = -11\r
\n" ); document.write( "\n" ); document.write( "==> -11 = -11\r
\n" ); document.write( "\n" ); document.write( "Hence the solution of y = -11 is correct.
\n" ); document.write( "
\n" );