document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=978018>Question 978018</A>: <I><SPAN STYLE=\"word-break: break-all;\"> question 1:     Before a TV set leaves the factory it is given a quality control check. The probability that the TV contains zero, one or two defects is .88, .08 and .04 respectively. In a sample of 16 TVs, find the probability that 9 will have no defects, 4 will have one defect and 3 will have two defects. Round your answer to 3 decimal places (beyond the zeros)\r<BR>\n" );
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document.write( "question 2:    A lot of 20 typewriters contains four defectives. 5 typewriters are randomly selected, what is the probability that at least two of the typewriters are defective? Round your answer to four decimal places.\r<BR>\n" );
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document.write( "question 3:   A jar contains 5 red, 6 white and 7 blue marbles. 5 marbles are randomly selected from the jar. Find the probability of drawing 2 red and 3 white marbles. Round your answers to 4 decimal places.<BR>\n" );
document.write( "Select one:<BR>\n" );
document.write( "a. .0233<BR>\n" );
document.write( "b. .0286<BR>\n" );
document.write( "c. .2907<BR>\n" );
document.write( "d. .111 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #599514 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=599514\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Q3:  Two red marbles can occur on the first or second draw or first and third, 10 ways altogether 5C2<BR>\n" );
document.write( "The first probability is (5/18) the second is (4/17).  The white marbles also have 10 ways they can be chosen (5C3=5C2)  (6/16)(5/15)(4/14)<BR>\n" );
document.write( "The denominators are always 18*17*16*15*14.  The numerators are always 5*4*6*5*4.  There are 10 ways to place the red balls.  Once they are placed, the white balls have no choice.  So there is one 10 in the numerator, not 2.\r<BR>\n" );
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document.write( "10*2400/18*17*16*15*14=0.0233  A\r<BR>\n" );
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document.write( "Q2:Probability of at least 2 = 1- probability of 1-probability of 0.<BR>\n" );
document.write( "Probability no defective is (16/20)(15/19)(14/18)(13/17)(12/16)=0.0188<BR>\n" );
document.write( "Probability of 1 defective is (16/20)(15/19)(14/18)(13/17)(4/16) *5  The defective typewriter can be 1st-5th, but the denominators stay the same, There are 5 ways it can happen.<BR>\n" );
document.write( "This probability is 0.4696\r<BR>\n" );
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document.write( "The total of the two is 0.4884<BR>\n" );
document.write( "Subtract from 1, and the probability of at least 2 is 0.5116.\r<BR>\n" );
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