document.write( "Question 977879: Find the equation of the tangent to the curve y= [4/(x^2)]+1 at the point where x=a. This tangent meets the axes at P(b,0) and Q(0,b). Find the value of a and of b. \n" ); document.write( "
Algebra.Com's Answer #599393 by Fombitz(32388)\"\" \"About 
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THe slope of the tangent line is equal to the value of the derivative at that point.
\n" ); document.write( "\"y=4x%5E%28-2%29%2B1\"
\n" ); document.write( "\"dy%2Fdx=-8x%5E%28-3%29=-8%2Fx%5E3\"
\n" ); document.write( "So at \"x=a\",
\n" ); document.write( "\"m=dy%2Fdx=-8%2Fa%5E3\"
\n" ); document.write( "Also when \"x=a\",
\n" ); document.write( "\"y=4%2Fa%5E2%2B1\"
\n" ); document.write( "Using the point-slope form of a line to find the tangent line,
\n" ); document.write( "\"y-%284%2Fa%5E2%2B1%29=%28-8%2Fa%5E3%29%28x-a%29\"
\n" ); document.write( "Multiply both sides by \"a%5E3\",
\n" ); document.write( "\"a%5E3y-4a-a%5E3=-8x%2B8a\"
\n" ); document.write( "\"highlight_green%28a%5E3y=-8x%2B12a%2Ba%5E3%29\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "When \"x=0\", \"y=b\",
\n" ); document.write( "\"a%5E3b=12a%2Ba%5E3\"
\n" ); document.write( "When \"x=b\",\"y=0\",
\n" ); document.write( "\"0=-8b%2B12a%2Ba%5E3\"
\n" ); document.write( "\"8b=12a%2Ba%5E3\"
\n" ); document.write( "So then,
\n" ); document.write( "\"a%5E3b=8b\"
\n" ); document.write( "\"a%5E3=8\"
\n" ); document.write( "\"highlight%28a=2%29\"
\n" ); document.write( "Then,
\n" ); document.write( "\"8b=12%282%29%2B8\"
\n" ); document.write( "\"8b=32\"
\n" ); document.write( "\"highlight%28b=4%29\"\r
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