document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=977824>Question 977824</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two trains are traveling on parallel tracks. One is a freight train and the other is a passenger train. The freight train travels at 25mph. If the freight train is 280 miles ahead of the passenger train and the passenger train is traveling at 60 mph , how long will the passenger train take to catch up with the freight train? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #599370 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=599370\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Algebraic solution<BR>\n" );
document.write( "t*(60-25)=280<BR>\n" );
document.write( "t*35=280<BR>\n" );
document.write( "t=280/35<BR>\n" );
document.write( "t=8 hours<BR>\n" );
document.write( "check<BR>\n" );
document.write( "8(60-25)=280<BR>\n" );
document.write( "8(35)=280<BR>\n" );
document.write( "280=280<BR>\n" );
document.write( "ok<BR>\n" );
document.write( "280 25 60 0 0<BR>\n" );
document.write( "Gaining speed 60-25= 35 mph<BR>\n" );
document.write( "Headstart 280 =280 miles<BR>\n" );
document.write( "Time to catch up =8 hours<BR>\n" );
document.write( "Time to catch up =480 minutes\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );