document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=83423>Question 83423</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve by first eliminating the decimal number<BR>\n" );
document.write( "0.5b+3.4=0.2b+12.4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #59934 by </B><A HREF=/tutors/aboutme.mpl?userid=uma><B>uma(370)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=59934\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.5b+3.4=0.2b+12.4\r<BR>\n" );
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document.write( "= (0.5)b + 3.4 = (0.2)b + 12.4\r<BR>\n" );
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document.write( "multiplying throughout by 10 [as there is 1 place after the decimal point],\r<BR>\n" );
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document.write( "5b + 34 = 2b + 124\r<BR>\n" );
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document.write( "==> 5b - 2b + 34 = 124\r<BR>\n" );
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document.write( "==> 3b + 34 = 124\r<BR>\n" );
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document.write( "==> 3b = 124 - 34\r<BR>\n" );
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document.write( "==> 3b = 90\r<BR>\n" );
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document.write( "==> b = 90/3\r<BR>\n" );
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document.write( "==> b = 30\r<BR>\n" );
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document.write( " </SPAN>\n" );
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