document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=977792>Question 977792</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for k<BR>\n" );
document.write( "LN(1/2)=5700K </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #599332 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=599332\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LN(1/2) is the natural logarithm which is base e, therefore<BR>\n" );
document.write( "LN(1/2) =  -6.9314718056e-1<BR>\n" );
document.write( "5700k =  -6.9314718056e-1<BR>\n" );
document.write( "k =  -6.9314718056e-1 /5700<BR>\n" );
document.write( "k = &#8722;1.216047685e&#8722;4<BR>\n" );
document.write( "k = &#8722;0.000121605<BR>\n" );
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