document.write( "Question 977750: Hello, the question asks to simplify the following algebraic expression. I apologize if this isn't the correct topic I have selected. The question is: \"Simplify the following algebraic expression:((x+1)^3 (3x-5) - (x+1)^2 (8x+3))/(x-4)(x+1)^3 \n" ); document.write( "
Algebra.Com's Answer #599331 by Boreal(15235)\"\" \"About 
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((x+1)^3 (3x-5) - (x+1)^2 (8x+3))/(x-4)(x+1)^3=\r
\n" ); document.write( "\n" ); document.write( "((x+1)^3)(3x-5))/(x-4) (x+1)^3 minus (x+1)^2(8x+3)/(x-4) (x+1)^3. Split the fraction.\r
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\n" ); document.write( "\n" ); document.write( "Cancel the (x+1)^3 completely in the first numerator term and (x+1)^2 in the second term.\r
\n" ); document.write( "\n" ); document.write( "This leaves
\n" ); document.write( "[(3x-5)/(x-4)] - ((8x+3)/(x+1)\r
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\n" ); document.write( "\n" ); document.write( "common denominator is (x-4)(x+1)
\n" ); document.write( "numerator will be (3x-5)(x+1)=3x^2-17x20 - [8x+3)(x-4)]
\n" ); document.write( "second part is 8x^2-29x-12,
\n" ); document.write( "3x^2-17x+20-8x^2+29x+12= {-5x^2+12x+32}/(x-4)(x+1)= -(5x^2-12x-32)/(x-4)(x+1)=
\n" ); document.write( "-(5x+8)(x-4)/(x-4)(x+1)= -(5x+8)/(x+1), because the (x-4) divide out.\r
\n" ); document.write( "\n" ); document.write( "Notice that I pull a minus sign out of the equation, because factoring -x^2 terms is difficult.\r
\n" ); document.write( "\n" ); document.write( "Do not multiply out the numerator at first. Split it into two fractions, cancel what you can, then put everything over a common denominator and simplify that. Often you can cancel further.\r
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