document.write( "Question 977781: The half-life of carbon-14 is 5770 years.
\n" ); document.write( "a. If you start with 1 gram of carbon-14, how long will it take for only 0.25 grams to remain?
\n" ); document.write( "b. Assuming that we start with 25 grams of carbon-14, find a formula that gives the amount of carbon-14 left after t years.
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Algebra.Com's Answer #599322 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
\"highlight_green%28y=p%2Ae%5E%28-kx%29%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1%2F2=1%2Ae%5E%28-k%2A5770%29\"
\n" ); document.write( "\"ln%281%2F2%29=-k%2A5770\"
\n" ); document.write( "\"ln%281%2F2%29%2F5770=-k\"
\n" ); document.write( "\"k=-ln%281%2F2%29%2F5770\"
\n" ); document.write( "\"highlight_green%28k=1.201%2A10%5E%28-4%29%29\"\r
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\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "(a):
\n" ); document.write( "\"0.25=1%2Ae%5E%28-1.201%2A10%5E%28-4%29%2Ax%29\"
\n" ); document.write( "\"ln%280.25%29=-1.201%2A10%5E%28-4%29%2Ax\"
\n" ); document.write( "\"x=ln%280.25%29%2F%28-1.201%2A10%5E%28-4%29%29\"
\n" ); document.write( "\"highlight%28x=11540%29\"\r
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\n" ); document.write( "\n" ); document.write( "(b):
\n" ); document.write( "\"ln%28y%29=ln%28p%29%2B%28-k%2At%29\"
\n" ); document.write( "\"ln%28y%29-ln%28p%29=-k%2At\"
\n" ); document.write( "\"kt=ln%28p%29-ln%28y%29\"
\n" ); document.write( "\"highlight_green%28t=%28ln%28p%29-ln%28y%29%29%2Fk%29\"
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