document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=977748>Question 977748</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Which one of the following has least value: 1/3, 2/3, 3/6, 3/4?\" </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #599310 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=599310\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Which one of the following has least value: 1/3, 2/3, 3/6, 3/4?\"<BR>\n" );
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document.write( "I would compare decimal values, as the other tutor did.<BR>\n" );
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document.write( "Another way is to find a common denominator.<BR>\n" );
document.write( "12 will work<BR>\n" );
document.write( "1/3 = 4/12<BR>\n" );
document.write( "2/3 = 8/12<BR>\n" );
document.write( "3/6 = 6/12<BR>\n" );
document.write( "3/4 = 9/12<BR>\n" );
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document.write( "That works well for these 4 values, but it can be cumbersome sometimes. </SPAN>\n" );
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