document.write( "Question 977688: you invested a total of php 10,000 at 4 1/2 percent and 5 1/2 percent simple interest. during 1 year the two accounts earned php 508.75 how much did you invest in each account? \n" ); document.write( "

Algebra.Com's Answer #599262 by richwmiller(17219) $\"\"$ $\"About$

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Total amount of money invested: $10000
\n" ); document.write( "x+y=10000,
\n" ); document.write( "Total yearly interest for the two accounts is: $508.75
\n" ); document.write( "0.045*x+0.055*y=508.75
\n" ); document.write( "x=10000-y
\n" ); document.write( "Substitute for x
\n" ); document.write( "0.045*(10000-y)+0.055*y=508.75
\n" ); document.write( "Multiply out
\n" ); document.write( "450.0-0.045*y+0.055*y=508.75
\n" ); document.write( "Combine like terms.
\n" ); document.write( "0.01*y=58.75
\n" ); document.write( "Isolate y
\n" ); document.write( "y=$ 5875.00 at 5.5% earns $323.125 interest
\n" ); document.write( "x=10000-y
\n" ); document.write( "Calculate x
\n" ); document.write( "x=$ 4125.00 at 4.5% earns $185.625 interest
\n" ); document.write( "Check
\n" ); document.write( "0.045*4125+0.055*5875=508.75
\n" ); document.write( "185.625+323.125=508.75
\n" ); document.write( "508.75=508.75
\n" ); document.write( "If 508.75=508.75 is TRUE and neither x nor y is negative then all is well
\n" ); document.write( "codeint1
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