document.write( "Question 977702: Jeremy paid for his breakfast with 36 coins consisting of nickels and dimes. If the bill was$3.50 then how many of each type of coin did he use
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Algebra.Com's Answer #599242 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! x+y=36, \n" ); document.write( "0.05*x+0.1*y=3.50 \n" ); document.write( "x=36-y \n" ); document.write( "Substitute for x \n" ); document.write( "0.05*(36-y)+0.1*y=3.5 \n" ); document.write( "Multiply out \n" ); document.write( "1.8-0.05*y+0.1*y=3.5 \n" ); document.write( "Combine like terms. \n" ); document.write( "0.05*y=1.7 \n" ); document.write( "Isolate y \n" ); document.write( "y=34 dimes \n" ); document.write( "x=36-y \n" ); document.write( "Calculate x \n" ); document.write( "x=2 nickels \n" ); document.write( "Check \n" ); document.write( "0.05*2+0.10*34=3.50 \n" ); document.write( "0.10+3.40=3.50 \n" ); document.write( "3.5=3.5\r \n" ); document.write( "\n" ); document.write( "codeint1 \n" ); document.write( " \n" ); document.write( " |