document.write( "Question 977702: Jeremy paid for his breakfast with 36 coins consisting of nickels and dimes. If the bill was$3.50 then how many of each type of coin did he use
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Algebra.Com's Answer #599242 by richwmiller(17219)\"\" \"About 
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x+y=36,
\n" ); document.write( "0.05*x+0.1*y=3.50
\n" ); document.write( "x=36-y
\n" ); document.write( "Substitute for x
\n" ); document.write( "0.05*(36-y)+0.1*y=3.5
\n" ); document.write( "Multiply out
\n" ); document.write( "1.8-0.05*y+0.1*y=3.5
\n" ); document.write( "Combine like terms.
\n" ); document.write( "0.05*y=1.7
\n" ); document.write( "Isolate y
\n" ); document.write( "y=34 dimes
\n" ); document.write( "x=36-y
\n" ); document.write( "Calculate x
\n" ); document.write( "x=2 nickels
\n" ); document.write( "Check
\n" ); document.write( "0.05*2+0.10*34=3.50
\n" ); document.write( "0.10+3.40=3.50
\n" ); document.write( "3.5=3.5\r
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