document.write( "Question 977632: Write as a single logarithm:
\n" ); document.write( "1/3(ln x - ln y) + 2 ln (x+1)
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Algebra.Com's Answer #599189 by Boreal(15235)\"\" \"About 
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1/3(ln x - ln y) + 2 ln (x+1)'\r
\n" ); document.write( "\n" ); document.write( "ln[(x/y)^1/3 * (x+1)^2]\r
\n" ); document.write( "\n" ); document.write( "Working on the inside
\n" ); document.write( "[x^1/3/y^1/3]*( x^2+2x+1)
\n" ); document.write( "That is [x^7/3+2x^4/3+x^1/3}/y^1/3\r
\n" ); document.write( "\n" ); document.write( "or ln{ (x^7+8x^4+x)/(y)}^1/3} I have to make the 2 an 8, because I am raising it, too, to the 1/3 power.
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