document.write( "Question 977558: Given a line with equation 6x-y=5. Write an equation in point-slope form of the line perpendicular to the given line through the point (2, -3). \n" ); document.write( "
Algebra.Com's Answer #599092 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( "First sort your equation into y = mx + c
\n" ); document.write( "6x - y = 5 => y = 6x - 5
\n" ); document.write( "Gradient = 6
\n" ); document.write( "Lines that are perpendicular to one another
\n" ); document.write( "have gradients that multiply together to give -1
\n" ); document.write( "m(1) x m(2) = -1
\n" ); document.write( "So, 6 x m(2) = -1
\n" ); document.write( "m(2) = -1/6
\n" ); document.write( "Now substitute this gradient into the line equation
\n" ); document.write( "y - b = m(x - a)
\n" ); document.write( "y - b = -1/6(x - a)
\n" ); document.write( "Substitute coordinates (2, -3)
\n" ); document.write( "y - (-3) = -1/6(x - 2)
\n" ); document.write( "y + 3 = -1/6x + 1/3
\n" ); document.write( "y = -1/6x + 1/3 - 9/3 (3 = 9/3)
\n" ); document.write( "y = -1/6x - 8/3
\n" ); document.write( "Multiply through by 12
\n" ); document.write( "12y = -2x - 24
\n" ); document.write( "Hope this helps:-) \n" ); document.write( "
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