document.write( "Question 977471: Hello!
\n" ); document.write( "How do I graph f(x)=(x^2-1)/(x+1)?
\n" ); document.write( "What does lim(x->1) (x^2-1)/(x+1) equal?\r
\n" ); document.write( "\n" ); document.write( "I graphed the function with a discontinuity at x=-1, but I'm not sure how my second question relates? Doesn't the limit have to be approaching an aymptote? Since it is approaching 1, I think y=0. I don't understand how that is possible if x=1 is not a discontinuity. My book says that there is a hole at x=1, but I have tried graphing it on a calculator and cannot seem to find it.\r
\n" ); document.write( "\n" ); document.write( "Thank you very much!\r
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Algebra.Com's Answer #599041 by FrankM(1040)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29=%28x%5E2-1%29%2F%28x%2B1%29\"\r
\n" ); document.write( "\n" ); document.write( "factors to \r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=%28x%2B1%29%28x-1%29%2F%28x%2B1%29\"\r
\n" ); document.write( "\n" ); document.write( "When you cancel x+1 you are left with f(x)=x-1\r
\n" ); document.write( "\n" ); document.write( "but must respect the 'hole' at x=-1
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