document.write( "Question 83381: Hello. Can someone tell me if I am correct? in words it is 2x minus the square root of seven divided by 2x plus the square root of seven. I got -------- -1 is this correct? 2x-sq7 divided by 2x +sq7 Thanks \n" ); document.write( "

Algebra.Com's Answer #59903 by Edwin McCravy(20086) $\"\"$ $\"About$

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Hello. Can someone tell me if I am correct? in words it is 2x minus the square root of seven divided by 2x plus the square root of seven. I got -------- -1 is this correct? 2x-sq7 divided by 2x +sq7 Thanks
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document.write( "No it isn't.\r\n" );
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document.write( "You must multiply by .\r\n" );
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document.write( "It's legal to multiply by that because it just equals to 1. \r\n" );
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document.write( "·\r\n" );
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document.write( "or:\r\n" );
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document.write( "Now FOIL out the numerator and denominator:\r\n" );
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document.write( "The two middle terms combine together in the \r\n" );
document.write( "top as \r\n" );
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document.write( "The two middle terms  CANCEL OUT in the bottom.\r\n" );
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document.write( "So we have as the final answer:\r\n" );
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document.write( "Notice that in the original expression there were radicals in BOTH\r\n" );
document.write( "the top AND the bottom.  In the final answer, the bottom contains NO\r\n" );
document.write( "radicals.  That's the idea -- to rewrite as an expression with NO\r\n" );
document.write( "radicals in the bottom.  The above method causes the radicals to\r\n" );
document.write( "cancel out in the bottom.\r\n" );
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document.write( "Edwin

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