document.write( "Question 977443: Use the given conditions to write an equation for each line in point-slope form. \r
\n" ); document.write( "\n" ); document.write( "Passing through (2, -3) and perpendicular to the line whose equation is y = 1/5 x + 6.
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Algebra.Com's Answer #598969 by anand429(138)\"\" \"About 
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Let required line be of form y = mx+c (slope-intercept form)
\n" ); document.write( "Since it is perpendicular to y = 1/5 x + 6
\n" ); document.write( "So, product of slopes = -1 (for two perpendicular lines m1 * m2 = -1)
\n" ); document.write( "So m * (1/5) = -1
\n" ); document.write( "=> m=-5
\n" ); document.write( "So our line becomes,
\n" ); document.write( "y = -5x + c
\n" ); document.write( "Now, this line passes through (2,-3) (As per ques.)
\n" ); document.write( "So putting the coordinates in above equation,
\n" ); document.write( "-3 = -5*2 +c
\n" ); document.write( "=> c = 7
\n" ); document.write( "So our line becomes,
\n" ); document.write( "y = -5x + 7.\r
\n" ); document.write( "\n" ); document.write( "Alternate method (Point slope form)
\n" ); document.write( "Using standard point-slope form and the condition that our line passes through (2,-3),we can write,
\n" ); document.write( "\"%28y-%28-3%29%29%2F%28x-2%29+=+m\"
\n" ); document.write( "Now , we have already found m as in previous solution as m=-5
\n" ); document.write( "So, our line is:
\n" ); document.write( "\"%28y-%28-3%29%29%2F%28x-2%29+=+-5\"
\n" ); document.write( "=> \"%28y%2B3%29%2F%28x-2%29+=+-5\" (Ans. in point slope form)
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