document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=977443>Question 977443</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the given conditions to write an equation for each line in point-slope form. \r<BR>\n" );
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document.write( "Passing through (2, -3) and perpendicular to the line whose equation is y = 1/5 x + 6. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #598967 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=598967\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "A line that is perpendicular to another <BR>\n" );
document.write( "line have the product of their gradients<BR>\n" );
document.write( "equaling -1 {(m(1) x m(2) = -1}<BR>\n" );
document.write( "With y = 1/5x + 6. The gradient is 1/5<BR>\n" );
document.write( "so, 1/5 x m(2) = -1<BR>\n" );
document.write( "m(2) = -5<BR>\n" );
document.write( "The line that passes through (2,-3)<BR>\n" );
document.write( "has the equation:-<BR>\n" );
document.write( "y - (-3) = -5(x - 2)<BR>\n" );
document.write( "y + 3 = -5x + 10<BR>\n" );
document.write( "y = -5x +10 - 3<BR>\n" );
document.write( "y = -5x + 7<BR>\n" );
document.write( "Hope this helps:-) </SPAN>\n" );
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