document.write( "Question 83391: radical 3 divided by radical 12 \n" ); document.write( "
Algebra.Com's Answer #59891 by bucky(2189)\"\" \"About 
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Given:
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\n" ); document.write( "\"sqrt%283%29%2Fsqrt%2812%29\"
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\n" ); document.write( "Let's first work on the denominator. \"sqrt%2812%29\" is equivalent to \"sqrt%284%2A3%29\"
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\n" ); document.write( "Then applying the rule that \"sqrt%28a%2Ab%29+=+sqrt%28a%29%2Asqrt%28b%29\" we can do another conversion to
\n" ); document.write( "see that:
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\n" ); document.write( "\"sqrt%2812%29+=+sqrt%284%2A3%29+=+sqrt%284%29%2Asqrt%283%29\"
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\n" ); document.write( "and for \"sqrt%284%29\" we can substitute its equivalent \"2\" so that the next conversion
\n" ); document.write( "in the chain is shown on the right side of the expressions:
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\n" ); document.write( "\"sqrt%2812%29+=+sqrt%284%2A3%29+=+sqrt%284%29%2Asqrt%283%29+=+2%2Asqrt%283%29\"
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\n" ); document.write( "In the original given expression of the problem, we can now replace \"sqrt%2812%29\"
\n" ); document.write( "by its equivalent form \"2%2Asqrt%283%29\". That replacement results in the original given
\n" ); document.write( "form of the problem becoming:
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\n" ); document.write( "\"sqrt%283%29%2Fsqrt%2812%29+=+sqrt%283%29%2F%282%2Asqrt%283%29%29\"
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\n" ); document.write( "Note that \"sqrt%283%29\" appears in as a factor in both the numerator and the denominator.
\n" ); document.write( "Therefore, it can be canceled and the result becomes:
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\n" ); document.write( "So the simplified or reduced form of the original expression that was given is:
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\n" ); document.write( "\"1%2F2\"
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\n" ); document.write( "Hope this gets you a little more familiar with radicals and some of the methods you can
\n" ); document.write( "use to simplify expressions involving them.
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