document.write( "Question 83385: Hello! My problem is this:
\n" ); document.write( "You can travel 40 miles on a motocycle in the same time it takes to travel 15 miles on a bike. If the motocycle rate is 20 miles per hour faster than the bike, what is the average of each?\r
\n" ); document.write( "\n" ); document.write( "I know that t=d/r so\r
\n" ); document.write( "\n" ); document.write( "40/x+20 = 15/x\r
\n" ); document.write( "\n" ); document.write( "I am not sure how to proceed and I have to show my work. Thanks
\n" ); document.write( "

Algebra.Com's Answer #59890 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
t = times for each, which are equal
\n" ); document.write( "t = distance/rate
\n" ); document.write( "Let m = motorcycles rate
\n" ); document.write( "\"t+=+40%2Fm\"
\n" ); document.write( "\"t+=+15%2F%28m-20%29\"
\n" ); document.write( "\"40%2Fm+=+15%2F%28m-20%29\"
\n" ); document.write( "multiply both sides by \"m%2A%28m-20%29\"
\n" ); document.write( "\"40%2A%28m-20%29+=+15m\"
\n" ); document.write( "\"40m+-800+=+15m\"
\n" ); document.write( "subtract 15m from both sides
\n" ); document.write( "\"25m+-+800+=+0\"
\n" ); document.write( "\"25m+=+800\"
\n" ); document.write( "\"m+=+32\" mph motorcycle speed
\n" ); document.write( "\"m-20+=+12\" mph bikes speed
\n" ); document.write( "check
\n" ); document.write( "\"40%2Fm+=+15%2F%28m-20%29\"
\n" ); document.write( "\"40%2F32+=+15%2F12\"
\n" ); document.write( "\"5%2F4+=+5%2F4\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );