document.write( "Question 83385: Hello! My problem is this:
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document.write( "You can travel 40 miles on a motocycle in the same time it takes to travel 15 miles on a bike. If the motocycle rate is 20 miles per hour faster than the bike, what is the average of each?\r
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document.write( "I know that t=d/r so\r
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document.write( "40/x+20 = 15/x\r
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document.write( "I am not sure how to proceed and I have to show my work. Thanks \n" );
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Algebra.Com's Answer #59890 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! t = times for each, which are equal \n" ); document.write( "t = distance/rate \n" ); document.write( "Let m = motorcycles rate \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "multiply both sides by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "subtract 15m from both sides \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "check \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " |