document.write( "Question 83379: Bob earned $6000 mowing lawns over the summer. He invested part of the $6000 at 3% simple interest and the rest of the $6000 at 4%. He earned a total of $220 in interest. How much did he invest at each rate? \n" ); document.write( "

Algebra.Com's Answer #59887 by josmiceli(19441) $\"\"$ $\"About$

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$\".03%2Ax+%2B+.04%2A%286000+-+x%29+=+220\"$
\n" ); document.write( " $\".03x+%2B+240+-+.04x+=+220\"$
\n" ); document.write( " $\"-.01x+=+-20\"$
\n" ); document.write( " $\".01x+=+20\"$
\n" ); document.write( " $\"x+=+2000\"$ dollars invested @ 3%
\n" ); document.write( " $\"6000+-+x+=+4000\"$ dollars invested @ 4%
\n" ); document.write( "check
\n" ); document.write( " $\".03%2Ax+%2B+.04%2A%286000+-+x%29+=+220\"$
\n" ); document.write( " $\".03%2A2000+%2B+.04%2A%286000+-+2000%29+=+220\"$
\n" ); document.write( " $\"60+%2B+240+-+80+=+220\"$
\n" ); document.write( " $\"220+=+220\"$
\n" ); document.write( "OK \n" ); document.write( "

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