document.write( "Question 977299: If x and y are two positive real nos. such that their sum is 1, then find the maximum value of \"xy%5E4+%2B+yx%5E4\"
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Algebra.Com's Answer #598851 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
If x and y are two positive real nos. such that their sum is 1, then find the maximum value of \"xy%5E4+%2B+yx%5E4\"
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document.write( "\"let\"\"z=xy%5E4+%2B+yx%5E4\"\r\n" );
document.write( "\"z=xy%28y%5E3%2Bx%5E3%29\"\r\n" );
document.write( "\"z=xy%28y%2Bx%29%28y%5E2-xy%2Bx%5E2%29\"\r\n" );
document.write( "\"z=xy%28y%2Bx%29%28y%5E2-xy%2Bx%5E2%29\"\r\n" );
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document.write( "Since x+y=1, substitute 1-x for y\r\n" );
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document.write( "\"z=x%281-x%29%28%281-x%29%2Bx%29%28%281-x%29%5E2-x%281-x%29%2Bx%5E2%29\"\r\n" );
document.write( "\"z=x%281-x%29%281%29%281-2x%2Bx%5E2-x%2Bx%5E2%2Bx%5E2%29\"\r\n" );
document.write( "\"z=x%281-x%29%281-3x%2B3x%5E2%29\"\r\n" );
document.write( "\"z=%28x-x%5E2%29%281-3x%2B3x%5E2%29\"\r\n" );
document.write( "\"z=x-3x%5E2%2B3x%5E3-x%5E2%2B3x%5E3-3x%5E4\"\r\n" );
document.write( "\"z=-3x%5E4%2B6x%5E3-4x%5E2%2Bx\"\r\n" );
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document.write( "If we can find A, B and nonnegative C such that\r\n" );
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document.write( "\"z=-3%28x%5E2%2BAx%2BB%29%5E2%2BC\"\r\n" );
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document.write( "then it's easy to see that z will have its maximum value \r\n" );
document.write( "when the quadratic \"x%5E2%2BAx%2BB\" equals 0, and that maximum\r\n" );
document.write( "value will be C. \r\n" );
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document.write( "Let's see if we can find such A, B, and C by equating\r\n" );
document.write( "coefficients:\r\n" );
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document.write( "\"-3x%5E4%2B6x%5E3-4x%5E2%2Bx+=+-3%28x%5E2%2BAx%2BB%29%5E2%2BC\"\r\n" );
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document.write( "\"-3x%5E4%2B6x%5E3-4x%5E2%2Bx+=+-3x%5E4-3A%5E2x%5E2-3B%5E2-6Ax%5E3-6Bx%5E2-6ABx%2BC\"\r\n" );
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document.write( "Equating coefficients of x³:  \"6+=+-6A\", or \"A+=+-1\"\r\n" );
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document.write( "Equating coefficients of x²:  \"-4+=+-3A%5E2-6B\"\r\n" );
document.write( "                              \"-4+=+-3%28-1%29%5E2-6B\"\r\n" );
document.write( "                              \"-4+=+-3%281%29-6B\"\r\n" );
document.write( "                              \"-4+=+-3-6B\"\r\n" );
document.write( "                              \"-1+=+-6B\"\r\n" );
document.write( "                              \"1%2F6+=+B\"\r\n" );
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document.write( "Equating coefficients of x:  \"1+=+-6AB\"\r\n" );
document.write( "                             \"1+=+-6%28-1%29%281%2F6%29\"\r\n" );
document.write( "                             \"1+=+1\"  \r\n" );
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document.write( "                              Already met.\r\n" );
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document.write( "Equating constant terms:      \"0+=+-3B%5E2%2BC\"\r\n" );
document.write( "                              \"0+=+-3%281%2F6%29%5E2%2BC\"\r\n" );
document.write( "                              \"0+=+-3%281%2F36%29%2BC\"\r\n" );
document.write( "                              \"0+=+-3%2F36%2BC\"\r\n" );
document.write( "                              \"3%2F36=C\"\r\n" );
document.write( "                              \"1%2F12=C\"\r\n" );
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document.write( "That's the answer \"C=1%2F12\"\r\n" );
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document.write( "z will take on that maximum value 1/12 when the quadratic \"x%5E2%2BAx%2BB\"\r\n" );
document.write( "takes on the value 0.  \r\n" );
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document.write( "\"x%5E2%2BAx%2BB+=+0\"\r\n" );
document.write( "\"x%5E2-1x%2B1%2F6+=+0\"\r\n" );
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document.write( "\"x+=+%281+%2B-+sqrt%281-2%2F3%29%29%2F2+\"\r\n" );
document.write( "\"x+=+%281+%2B-+sqrt%281%2F3%29%29%2F2+\"\r\n" );
document.write( "\"x+=+%281+%2B-+sqrt%283%29%2F3%29%2F2+\"\r\n" );
document.write( "Multiply top and bottom by 3\r\n" );
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document.write( "\"x+=+%283+%2B-+sqrt%283%29%29%2F6\"\r\n" );
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document.write( "So there are two points where z reaches the maximum value of \"1%2F12\"\r\n" );
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document.write( "They are \"%28+matrix%281%2C3%2C%283+%2B-+sqrt%283%29%29%2F6%2C%22%2C%22%2C1%2F12%29%29\"\r\n" );
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document.write( "Edwin

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