document.write( "Question 977313: Solve the system, if possible. (If the system is inconsistent, enter INCONSISTENT. If the system is dependent, enter DEPENDENT.)
\n" ); document.write( "4a − 3b = 1
\n" ); document.write( "6a − 8c = 1
\n" ); document.write( "2b − 4c = 0
\n" ); document.write( "
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Algebra.Com's Answer #598826 by Alan3354(69443)\"\" \"About 
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Solve the system, if possible. (If the system is inconsistent, enter INCONSISTENT. If the system is dependent, enter DEPENDENT.)
\n" ); document.write( "4a − 3b = 1
\n" ); document.write( "6a − 8c = 1
\n" ); document.write( "2b − 4c = 0
\n" ); document.write( "-----------------------
\n" ); document.write( "What's the problem with the minus signs?
\n" ); document.write( "4a - 3b = 1
\n" ); document.write( "6a - 8c = 1
\n" ); document.write( "2b - 4c = 0 --> b - 2c = 0 --> b = 2c
\n" ); document.write( "---------------
\n" ); document.write( "Sub for b in the 1st equation.
\n" ); document.write( "4a - 3b = 1 --> 4a - 3(2c) = 1 --> 4a - 6c = 1
\n" ); document.write( "6a - 8c = 1
\n" ); document.write( "--------------
\n" ); document.write( "4a - 6c = 1 Eqn A
\n" ); document.write( "6a - 8c = 1 Eqn B
\n" ); document.write( "------------------
\n" ); document.write( "12a - 18c = 3 Eqn A times 3
\n" ); document.write( "12a - 16c = 2 Eqn B times 2
\n" ); document.write( "-------------------------------------- Subtract
\n" ); document.write( "-2c = 1
\n" ); document.write( "c = -1/2 ****************************************************
\n" ); document.write( "------
\n" ); document.write( "4a - 6c = 1
\n" ); document.write( "4a + 3 = 1
\n" ); document.write( "a = -1/2 ****************************************************
\n" ); document.write( "--------
\n" ); document.write( "4a - 3b = 1
\n" ); document.write( "-2 - 3b = 1
\n" ); document.write( "b = -1 *******************************************************
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