document.write( "Question 977313: Solve the system, if possible. (If the system is inconsistent, enter INCONSISTENT. If the system is dependent, enter DEPENDENT.)
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document.write( "4a − 3b = 1
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document.write( "6a − 8c = 1
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document.write( "2b − 4c = 0
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document.write( "
Algebra.Com's Answer #598826 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Solve the system, if possible. (If the system is inconsistent, enter INCONSISTENT. If the system is dependent, enter DEPENDENT.) \n" ); document.write( "4a − 3b = 1 \n" ); document.write( "6a − 8c = 1 \n" ); document.write( "2b − 4c = 0 \n" ); document.write( "----------------------- \n" ); document.write( "What's the problem with the minus signs? \n" ); document.write( "4a - 3b = 1 \n" ); document.write( "6a - 8c = 1 \n" ); document.write( "2b - 4c = 0 --> b - 2c = 0 --> b = 2c \n" ); document.write( "--------------- \n" ); document.write( "Sub for b in the 1st equation. \n" ); document.write( "4a - 3b = 1 --> 4a - 3(2c) = 1 --> 4a - 6c = 1 \n" ); document.write( "6a - 8c = 1 \n" ); document.write( "-------------- \n" ); document.write( "4a - 6c = 1 Eqn A \n" ); document.write( "6a - 8c = 1 Eqn B \n" ); document.write( "------------------ \n" ); document.write( "12a - 18c = 3 Eqn A times 3 \n" ); document.write( "12a - 16c = 2 Eqn B times 2 \n" ); document.write( "-------------------------------------- Subtract \n" ); document.write( "-2c = 1 \n" ); document.write( "c = -1/2 **************************************************** \n" ); document.write( "------ \n" ); document.write( "4a - 6c = 1 \n" ); document.write( "4a + 3 = 1 \n" ); document.write( "a = -1/2 **************************************************** \n" ); document.write( "-------- \n" ); document.write( "4a - 3b = 1 \n" ); document.write( "-2 - 3b = 1 \n" ); document.write( "b = -1 ******************************************************* \n" ); document.write( " \n" ); document.write( " |