document.write( "Question 976883: 3/20, 3/10, 3/8, 3/4, 3/2, 3,...,....,....,...... \n" ); document.write( "
Algebra.Com's Answer #598778 by Edwin McCravy(20056)\"\" \"About 
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document.write( "3/20, 3/10, 3/8, 3/4, 3/2, 3/1,...,....,....,......\r\n" );
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document.write( "The sequence of numerators is simply \"all 3's\":\r\n" );
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document.write( "3, 3, 3, 3, 3, 3,...\r\n" );
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document.write( "We look at the sequence of denominators:\r\n" );
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document.write( "20, 10, 8, 4, 2, 1, ?, ?, ?, ?\r\n" );
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document.write( "Start with 20\r\n" );
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document.write( "Divide by 2, get 10\r\n" );
document.write( "Subtract 2, get 8\r\n" );
document.write( "Divide by 2, get 4\r\n" );
document.write( "Subtract 2, get 2\r\n" );
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document.write( "To continue the pattern of dividing by 2, then subtracting 2, over and over, \r\n" );
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document.write( "Divide by 2, get 1\r\n" );
document.write( "Subtract 2, get -1\r\n" );
document.write( "Divide by 2, get -1/2\r\n" );
document.write( "Subtract 2, get -1/2 - 2 = -1/2 - 4/2 = -5/2\r\n" );
document.write( "Divide by 2, get -5/4\r\n" );
document.write( "So the sequence of denominators is\r\n" );
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document.write( "20, 10, 8, 4, 2, 1, -1, -1/2, -5/2, -5/4\r\n" );
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document.write( "The sequence of numerators is \"all 3's\", so the sequence is\r\n" );
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document.write( "3/20, 3/10, 3/8, 3/4, 3/2, 3/1, 3/(-1), 3/(-1/2), 3/(-5/2), 3/(-5/4), ...\r\n" );
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document.write( "Simplifying:\r\n" );
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document.write( "3/20, 3/10, 3/8, 3/4, 3/2, 3, -3, -6, -6/5, -12/5, ...\r\n" );
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document.write( "Edwin
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