document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=977227>Question 977227</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find three consecutive number such that six times the smallest number is equal to double the sum of other two. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #598752 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=598752\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We have three consecutive numbers, represented by: x, x+1, x+2. Then:<BR>\n" );
document.write( "6x= 2(x+1+x+2)<BR>\n" );
document.write( "6x= 2(2x+3)<BR>\n" );
document.write( "6x= 4x+6<BR>\n" );
document.write( "2x= 6<BR>\n" );
document.write( "x= 3<BR>\n" );
document.write( "The numbers are 3, 4, and 5<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "6*3= 18 and 2(4+5)= 18 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );