document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=977226>Question 977226</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I haved worked this question out to be x=250. What is your answer:\r<BR>\n" );
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document.write( "Suppose that the daily cost C of manufacturing bicycles is given by <BR>\n" );
document.write( "C(x)= 80x + 5000. Then the average daily cost C is given by\r<BR>\n" );
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document.write( "C(x)=  80x+5000<BR>\n" );
document.write( "       --------<BR>\n" );
document.write( "          x<BR>\n" );
document.write( "how many bicycles must be produced each day for the average cost to be no more than $100? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #598740 by </B><A HREF=/tutors/aboutme.mpl?userid=femi27><B>femi27(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=femi27><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=598740\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Yes you are right but you could set it out like this:<BR>\n" );
document.write( "(80x+5000)/x<=100 so that we have 80x+5000<=100x, if we collect like terms, this inequality turns to: 80x-100x<=-5000 so -20x<=-5000 and x>=250. <BR>\n" );
document.write( "What you left out is the inequality sign, everything else is fine.<BR>\n" );
document.write( "Hope this helps! </SPAN>\n" );
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