document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=83362>Question 83362</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help. I am pulling my hair out over this? <BR>\n" );
document.write( "For the equation in exercises 26, create a suitable table of values, and sketch the graph (including the axis of symmetry). Identify the axis of symmetry, identify the vertex point, the graph&#8217;s direction, and any axis intercepts gleaned from the table or graph. \r<BR>\n" );
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document.write( "y=x^2-5x+3<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #59872 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=59872\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> for a parabola of the form y=ax^2+bx+c, the equation of the axis of symmetry is x=-b/2a ... in this case x=5/2\r<BR>\n" );
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document.write( "the vertex lies on the axis of symmetry and can be found by substituting the x value from the axis of symmetry into the equation\r<BR>\n" );
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document.write( "y=(5/2)^2-5(5/2)+3=(25/4)-(25/2)+3=-13/4 ... vertex is ((5/2),(-13/4))\r<BR>\n" );
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document.write( "a good table of values would be ... (-1,9), (0,3), (1,-1), (2,-3), (3,-3), (4,-1), (5,3), (6,9)\r<BR>\n" );
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document.write( "since the coefficient of the x^2 term is positive, the parabola opens upward\r<BR>\n" );
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document.write( "the y-intercept is in the table of values (0,3)\r<BR>\n" );
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document.write( "there are 2 x-intercepts, one between (0,3) and (1,-1); and another between (4,-1) and (5,3) </SPAN>\n" );
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