document.write( "Question 11662: 2a+3b+c/2d when a=2, b=0 c=3 and d=-5 \r
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Algebra.Com's Answer #5987 by glabow(165)\"\" \"About 
You can put this solution on YOUR website!
It's not a problem if you remember: you do all grouped operations first (that's operations in parentheses), then you do all multiplies and divides, then all adds and subtracts.
\n" ); document.write( "There are no groups in 2a+3b+c/2d. So you do the multiplies followed by the divide.
\n" ); document.write( "2 x 2 + 3 x 0 + 3 / 2 x (-5) [substituting 2 for a, 0 for b, 3 for c, and -5 for d]
\n" ); document.write( "\"4+%2B+0+%2B+%283%2F2%29+%28-5%29+=+4+%2B+0+%2B+%28-15%2F2%29=8%2F2+-+15%2F2=-7%2F2\"
\n" ); document.write( "Or, -3 1/2\r
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