document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=977172>Question 977172</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Shopping at Super Sale Days, Martha buys her children 3 shirts and 2 pairs of pants for $85.50. She returns during the sale and buys 4 more shirts and 3 more pairs of pants for $123. What is the sale price of the shirts and pants? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #598678 by </B><A HREF=/tutors/aboutme.mpl?userid=FrankM><B>FrankM(1040)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=FrankM><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=FrankM><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=598678\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3S+2P=85.50<BR>\n" );
document.write( "4S+3P=123\r<BR>\n" );
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document.write( "Let's multiply the first equation by 3 and the second by 2\r<BR>\n" );
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document.write( "9S+6P=256.50<BR>\n" );
document.write( "8S+6P=246.00\r<BR>\n" );
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document.write( "Subtract the second equation from the first.\r<BR>\n" );
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document.write( "S=10.50\r<BR>\n" );
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document.write( "and put that back into first equation\r<BR>\n" );
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document.write( "3(10.50)+2P=85.50\r<BR>\n" );
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document.write( "31.50+2P=85.50\r<BR>\n" );
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document.write( "2P=54\r<BR>\n" );
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document.write( "P=27\r<BR>\n" );
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document.write( "Shirts are $10.50 Pants $27.00 </SPAN>\n" );
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