document.write( "Question 977156: In a race the top speed of one car is 9/10 of the top speed of a another. After one half hour faster car is 10 km ahead of the slower car find the rate of each car assuming they started side-by-side. \n" ); document.write( "
Algebra.Com's Answer #598673 by ankor@dixie-net.com(22740)\"\" \"About 
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In a race the top speed of one car is 9/10 of the top speed of a another.
\n" ); document.write( " After one half hour faster car is 10 km ahead of the slower car.
\n" ); document.write( " find the rate of each car assuming they started side-by-side.
\n" ); document.write( ":
\n" ); document.write( "let s = speed of the faster car
\n" ); document.write( "then
\n" ); document.write( ".9s = speed of the slower
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\n" ); document.write( "Write a distance equation; dist = speed * time, use .5 hrs for travel time
\n" ); document.write( ".5s = .5(.9s) + 10
\n" ); document.write( ".5s = .45s + 10
\n" ); document.write( ".5s - .45s = 10
\n" ); document.write( ".05s = 10
\n" ); document.write( "s = 10/.05
\n" ); document.write( "s = 200 km/hr is the speed of the faster car
\n" ); document.write( "then
\n" ); document.write( ".9(200) = 180 km/hr is the speed of the slower
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this, find the actual dist each traveled
\n" ); document.write( "200*.5 = 100 km
\n" ); document.write( "180*.5 = 90 km
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\n" ); document.write( "dist dif: 10 km
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