document.write( "Question 975570: Rogelio and Jin are looking up at the top of the tower that is 36.6m tall. If Jin is looking up at an angle of elevation of 24 degree, and Rogelio is on the opposite side of the tower looking up at an angle of 17 degree, How far apart are Rogelio and Jin to the nearest meter? Assume their eyes are both 1.8m meter off the ground. \n" ); document.write( "
Algebra.Com's Answer #598672 by Cromlix(4381)\"\" \"About 
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Consider the problem as two right angled
\n" ); document.write( "triangles back to back.
\n" ); document.write( "Rogelio stands on one side of the tower
\n" ); document.write( "and Jin stands on the other.
\n" ); document.write( "Now we have the distance from Rogelio
\n" ); document.write( "to the tower and the distance of Jin
\n" ); document.write( "from the tower. These represent the
\n" ); document.write( "adjacent side of both the triangles.
\n" ); document.write( "The opposite side is the tower, but as
\n" ); document.write( "both men's eyes are 1.8 metres from the ground
\n" ); document.write( "then the opposite side is given the value
\n" ); document.write( "36.6 - 1.8 = 34.8 metres.
\n" ); document.write( "We will use the tan ratio as we have an angle
\n" ); document.write( "and an opposite side. We must find the lengths
\n" ); document.write( "of the two adjacents.
\n" ); document.write( "Rogelio:
\n" ); document.write( "Tan 17 = 34.8/adjacent
\n" ); document.write( "Adjacent = 34.8/tan 17 = 113.8 metres
\n" ); document.write( "Jin
\n" ); document.write( "Tan 24 = 34.8/adjacent
\n" ); document.write( "Adjacent = 34.8/tan 24 = 78.2 metres
\n" ); document.write( "Add the two adjacent values
\n" ); document.write( "113.8 + 78.2 = 192 metres.
\n" ); document.write( "This is how far apart Rogelio and Jin are.
\n" ); document.write( "Hope this helps:-) \n" ); document.write( "
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