document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=83369>Question 83369</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers. \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #59866 by </B><A HREF=/tutors/aboutme.mpl?userid=jmichau3><B>jmichau3(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jmichau3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=59866\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ok well the best way to start is with an even interger.<BR>\n" );
document.write( "Let 2n = an even integer<BR>\n" );
document.write( "Then the next consecutive even integer will be 2n+2 and then 2n+4 will be the third.<BR>\n" );
document.write( "then use what is given so come up with<BR>\n" );
document.write( "(2n+4)^2 = (2n+2)^2 + 76.<BR>\n" );
document.write( "Now solve for n, Which I will leave for you to do...<BR>\n" );
document.write( "once you solve forn n, make sure to plug it back into your equations (ie 2n,2n+2, 2n+4) to find your consecutive numbers\r<BR>\n" );
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document.write( "If anything is unclear feel free to email me </SPAN>\n" );
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