document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=977030>Question 977030</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a three digit number unit's digit, ten's digit and hundred's are in the ratio of 1:2:3. If the difference in the original number and the number obtained by reversing the digit is 594 find the number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #598519 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=598519\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In a three digit number unit's digit, ten's digit and hundred's are in the ratio of 1:2:3. If the difference in the original number and the number obtained by reversing the digit is 594 find the number?<BR>\n" );
document.write( "***<BR>\n" );
document.write( "let u=units digit<BR>\n" );
document.write( "let t=tens digit<BR>\n" );
document.write( "let h=hundredth digit<BR>\n" );
document.write( "..<BR>\n" );
document.write( "(100h+10t+u)-(100u+10t+h)=594<BR>\n" );
document.write( "100h+10t+u-100u-10t-h)=594<BR>\n" );
document.write( "99h-99u=594<BR>\n" );
document.write( "h=3u<BR>\n" );
document.write( "99*3u-99u=594<BR>\n" );
document.write( "297u-99u=594<BR>\n" );
document.write( "198u=594<BR>\n" );
document.write( "u=3<BR>\n" );
document.write( "h=3u=9<BR>\n" );
document.write( "t=2u=6<BR>\n" );
document.write( "..<BR>\n" );
document.write( "check:<BR>\n" );
document.write( "100h+10t+u=900+60+3=963<BR>\n" );
document.write( "100u+10t+h=300+60+9=369<BR>\n" );
document.write( "difference: 963-369=594 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );