document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=83358>Question 83358</A>: <I><SPAN STYLE=\"word-break: break-all;\"> using the 45 45 90 triangle formula , if a traingle has a side of 8cm and a 45 degree angle, how would you solve for the other sides </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #59849 by </B><A HREF=/tutors/aboutme.mpl?userid=vertciel><B>vertciel(183)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vertciel><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=59849\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well, you know the ratios are:\r<BR>\n" );
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document.write( "45/1 : 45/1 : 90/sqrt(2).\r<BR>\n" );
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document.write( "So the hypotenuse has the ratio of sqrt(2).\r<BR>\n" );
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document.write( "You would multiply the side of 8 cm with sqrt(2), and your hypotenuse would be 8&#8730;2.  </SPAN>\n" );
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