document.write( "Question 976954: What are the mean and standard deviation of the data -6,12,2,-4,1,6,0,3?
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document.write( "a. the mean is 2 1/3 and the standard deviation is approximately 5.6252
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document.write( "b. The mean is 2 1/3 and the standard deviation is 5.
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document.write( "c. The mean is 1 3/4 and the standard deviation is approsimately 5.6252
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document.write( "d. The mean is 4.86 and the standard deviation is 5.63. \n" );
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Algebra.Com's Answer #598433 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! x =-6+ 12 + 2 + (-4) + 1 + 6 + 0 + 3 = 14 \n" ); document.write( "14/8 mean = 1 3/4 \n" ); document.write( "(x - mean) \n" ); document.write( "-7.75, 10.25, 0.25, -5.75, -0.75, 4.25 \n" ); document.write( "- 1.75, 1.25. \n" ); document.write( " (x - mean)^2 \n" ); document.write( "-60.0625 + 105.0625+ 0.0625+ 33.0625+ 0.5625+ \n" ); document.write( "18.0625 + 3.0625 + 1.5625 \n" ); document.write( "Total = 221.5 \n" ); document.write( "Divide by 8 - 1 = 7 \n" ); document.write( "= 31.643 \n" ); document.write( "Square root answer. \n" ); document.write( "= 5.6252 (Standard deviation) \n" ); document.write( "Answer c is correct \n" ); document.write( "Mean is 1 3/4 and SD is 5.6252 \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |