document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=976938>Question 976938</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At a campsite, I pound a post into the ground 1 meter from my tent.  If my angle of elevation is 57 degrees, how much rope do I need from the post to the top edge of my tent? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #598427 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=598427\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Consider that the rope to the tent<BR>\n" );
document.write( "is the hypotenuse of a right angled triangle.<BR>\n" );
document.write( "The distance of 1 metre on ground is the <BR>\n" );
document.write( "adjacent side of the triangle.<BR>\n" );
document.write( "Using trigonometric ratio:-<BR>\n" );
document.write( "Cosine = Adjacent/Hypotenuse<BR>\n" );
document.write( "Cosine 57 degrees = 1 metre/ Hypotenuse<BR>\n" );
document.write( "Therefore Hypotenuse (Length of rope)<BR>\n" );
document.write( "= 1 metre/ Cosine 57 degrees<BR>\n" );
document.write( "= 1.84 metres (2 decimal places)<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
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