document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=976910>Question 976910</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a number consists of three digit whose sum is 17 . The middle digit is one more than the sum of the other two digits. If digits are reversed, the new number is 396 less than the original number. What is the number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #598407 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=598407\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a+b+c=17<BR>\n" );
document.write( "b=1+a+c<BR>\n" );
document.write( "100a+10b+c-100c-10b-a=396<BR>\n" );
document.write( "99a-99c=396<BR>\n" );
document.write( "a-c=4<BR>\n" );
document.write( "a=c+4<BR>\n" );
document.write( "b=1+a+c<BR>\n" );
document.write( "b=1+c+4+c<BR>\n" );
document.write( "b=5+2c<BR>\n" );
document.write( "a+b+c=17\r<BR>\n" );
document.write( "\n" );
document.write( "(c+4)+[5+2c]+c=17<BR>\n" );
document.write( "4c+9=17<BR>\n" );
document.write( "4c=8<BR>\n" );
document.write( "c=2<BR>\n" );
document.write( "a=6<BR>\n" );
document.write( "b=9<BR>\n" );
document.write( "number is 692<BR>\n" );
document.write( "check<BR>\n" );
document.write( "692-296=396<BR>\n" );
document.write( "ok\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );