document.write( "Question 11521: I need to understand how to solve this equation and to find the value of x.
\n" ); document.write( "1/2(2x-1)+1/4(x-2)=4
\n" ); document.write( "Thanks \n" ); document.write( "
Algebra.Com's Answer #5984 by elima(1433)\"\" \"About 
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1/2(2x-1)+1/4(x-2)=4\r
\n" ); document.write( "\n" ); document.write( "You begin by multiplying 1/2(2x-1)= 2x-1/2\r
\n" ); document.write( "\n" ); document.write( "then 1/4(x-2) = x-2/4\r
\n" ); document.write( "\n" ); document.write( "Now you have:\r
\n" ); document.write( "\n" ); document.write( "2x-1/2+x-2/4=4\r
\n" ); document.write( "\n" ); document.write( "To add the left side together you need common denominators,which would be 4.\r
\n" ); document.write( "\n" ); document.write( "So; 2(2x-1)/4+x-2/4=4
\n" ); document.write( "Now you can add the left side together:
\n" ); document.write( "4x-2/4+x-2/4 = 5x-4/4
\n" ); document.write( "5x-4/4=4
\n" ); document.write( "Now multiply 4 to both sides so you can get rid of the 4 denominator.
\n" ); document.write( "5x-4 = 16\r
\n" ); document.write( "\n" ); document.write( "add 4 to both sides so you can get 5x by itself.
\n" ); document.write( "5x=20
\n" ); document.write( "Divide both sides by 5;\r
\n" ); document.write( "\n" ); document.write( "x=4
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