document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=976855>Question 976855</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An automobile radiator holds 16 liters of fluid. There is currently a mixture in the radiator that is 80% antifreeze and 20% water. How much of the mixture should be drained and reduced by pure antifreeze so that the resulting mixture is 90 % antifreeze? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #598346 by </B><A HREF=/tutors/aboutme.mpl?userid=FrankM><B>FrankM(1040)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=FrankM><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=FrankM><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=598346\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 90% of 16l is 14.4l antifreeze and 1.6l water. \r<BR>\n" );
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document.write( "What we have now is 20% water. Since we can only have 1.6l water, 8l of the old mix is all we can keep. Dump out 8l and add pure antifreeze to get a 90% mix. \r<BR>\n" );
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