document.write( "Question 976729: What is the total interest earned after one year when $100,000 is invested, part at 6% annual interest rate and the remaining part at 7.5% annual interest rate \n" ); document.write( "
Algebra.Com's Answer #598333 by jim_thompson5910(35256)\"\" \"About 
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x = amount of money invested at 6%
\n" ); document.write( "y = amount of money invested at 7.5%\r
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\n" ); document.write( "\n" ); document.write( "x+y = 100,000
\n" ); document.write( "y = 100,000 - x\r
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\n" ); document.write( "\n" ); document.write( "Interest Earned for the 6% account = 0.06x
\n" ); document.write( "Interest Earned for the 7.5% account = 0.075y = 0.075(100,000 - x) = 7500 - 0.075x\r
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\n" ); document.write( "\n" ); document.write( "Add up the amounts:
\n" ); document.write( "0.06x+0.075x = 0.135x\r
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\n" ); document.write( "\n" ); document.write( "So we can get as far as 0.135x. We can't go any further unless we know either x or y.
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