document.write( "Question 976797: What is the value of the derivative of |x-1|+|x-3| at x=2 is:
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\n" ); document.write( "c)2
\n" ); document.write( "d)not defined
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Algebra.Com's Answer #598330 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

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\n" ); document.write( "\n" ); document.write( "if \"x=2\", we have\r
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\n" ); document.write( "\n" ); document.write( "\"%28d%2Fdx%29%28abs%28x-1%29%2Babs%28x-3%29%29+=+-1%2F1%2B1%2F1\"\r
\n" ); document.write( "\n" ); document.write( "\"%28d%2Fdx%29%28abs%28x-1%29%2Babs%28x-3%29%29+=+-1%2B1\"\r
\n" ); document.write( "\n" ); document.write( "\"%28d%2Fdx%29%28abs%28x-1%29%2Babs%28x-3%29%29+=+0\"\r
\n" ); document.write( "\n" ); document.write( "so, your answer is b)\"0\"\r
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