document.write( "Question 976837: The shaded rectangle is twice as long as it is wide.
\n" ); document.write( "The perimeter of the rectangle is 30cm.
\n" ); document.write( "What is the area of the rectangle?
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Algebra.Com's Answer #598329 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
w and L, width and length\r
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\n" ); document.write( "\n" ); document.write( "FORMULAS
\n" ); document.write( "wL=A for area
\n" ); document.write( "2w+2L=p for perimeter\r
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\n" ); document.write( "\n" ); document.write( "DESCRIPTION
\n" ); document.write( "\"system%28L=2w%2Cp=30%29\"\r
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\n" ); document.write( "\n" ); document.write( "Look at system:
\n" ); document.write( "\"system%28wL=A%2C2w%2B2L=p%2CL=2w%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"w%2A2w=A\"
\n" ); document.write( "\"2w%5E2=A\"
\n" ); document.write( "-
\n" ); document.write( "\"2w%2B2%2A2w=p\"
\n" ); document.write( "\"6w=p\"
\n" ); document.write( "\"highlight_green%28w=p%2F6%29\"
\n" ); document.write( "-
\n" ); document.write( "\"2L=p-2w\"
\n" ); document.write( "\"2L=p-2%28p%2F6%29\"
\n" ); document.write( "\"2L=p-p%2F3\"
\n" ); document.write( "\"2L=%283p-p%29%2F3\"
\n" ); document.write( "\"2L=2p%2F3\"
\n" ); document.write( "\"highlight_green%28L=p%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "p was given a value, 30, but L and w were only described as unknown variables. Now, they can be evaluated in terms of p.\r
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\n" ); document.write( "\n" ); document.write( "Question was, find area.
\n" ); document.write( "\"A=wL\"
\n" ); document.write( "\"A=%28p%2F6%29%28p%2F3%29\"
\n" ); document.write( "\"highlight%28A=%28p%5E2%29%2F18%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28highlight_green%28A=50%29%29\"
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